Physics Post 15

For this physics post I will be explaining the picture I took of my phone on the side of a box while comparing it to my group's egg drop lab. This relates to our lab because it represents how our egg in the box fell. Of course, this is a hypothesis because we do not know exactly how the egg fell since we there were three drops total and we did not openthe box in between the drops. Our strategy was to increase the cushion in the box in order to increase stopping time for the egg therefore decreasing the force placed on the actual egg. This failed because after dropping the box with the egg three times, the egg was dislodged from it's resting place in the middle of the box and it went to the outer edge. This is represented in the picture I took (although the egg was on the inside not the outside). When the egg was dropped like this, there was no cushion for the egg to slow down with. After falling two stories, the force that was imparted on the egg from the sudden stop easily broke the shell.

Physics Post 14

For this physics post I will be explaining the picture I took of me dropping a calculator on my pillow. This shows how the force that is imparted on an object hitting the ground (or my bed in this case) can be reduced by putting some sort of cushion to increase the time it takes to stop. By increasing the stopping time, which is inversely related to the force, you decrease the objects chance of a stop that is too sudden. In this specific situation, the pillow is more than enough to cushion a .2kg calculator falling from 1 meter. Although in movies, stunt doubles often have very large air cushions which will help them to fall from heights without injury.

Physics Post 13

For this physics post I will be explaining a picture I took of a marble being flicked at a thumb drive. For this picture, we are assuming that the thumb drive is the same mass as the marble, and the marble contacts the thumb drive perfectly. If we assume those properties are in effect, the initial velocity of the marble should become the final velocity of the thumb drive and the thumb drive, which is at rest, should move in a direction opposite of the incoming marble. Also, the marbles final velocity should be zero. This shows the conservation of momentum. Since the items are of equal mass they should perfectly exchange their velocities; the equation m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final) proves this. When you condense the formula to m(v1+v2)initial = m(v1+v2)final (since m1=m2 you can condense them and put them out of the parentheses), and you cancel out the masses (since they remain constant) you are left with v1+v2(initial) = v1+v2(final). This shows that if v1 = something and v2 = 0 and if v1's initial velocity is transferred into v2's final velocity, v1 must become 0 in order to balance the equation.

Physics Post 12

For this physics post I will be explaining the picture I took of me about to drop a stuffed dog. This demonstrates change in momentum, or rather, the change in momentum that is going to take place when I drop the stuffed dog and it stops moving when it lands on my bed. Since I am dropping the stuffed dog on earth, gravity will make the stuffed dog accelerate down, in a negative y direction. Assuming that the mass of the dog is 0.20 kg and it's velocity downwards is 3.00m/s we can find the change in momentum by subtracting the initial momentum from the final momentum. Since the stuffed dog will remain on the bed after landing, it's final momentum is zero. It's initial momentum will be mass times negative velocity: 0.20 kg x -(3.00m/s) = -0.60 kg x m/s. Therefore, the change in momentum or delta p will be positive 0.60 kg x m/s which makes sense since it was initially traveling downwards or negative and the change from negative to zero is positive.